我正在构建一个多标签文本分类算法。下面是我labels.txt文件的一个片段，我希望将这些记录转换成一个字典，字典的键是id，对应的值是包含类别的元组或列表，即{id:(cat1,cat2)}。这些记录之间没有换行符。我不知道如何将这种数据转换成字典。

B0027DQHA0  Movies & TV, TV  Music, Classical0756400120  Books, Literature & Fiction, Anthologies & Literary Collections, General  Books, Literature & Fiction, United States  Books, Science Fiction & Fantasy, Science Fiction, Anthologies  Books, Science Fiction & Fantasy, Science Fiction, Short StoriesB0000012D5  Music, Blues  Music, Pop  Music, R&B

回答：

如果类别名称总是以空格缩进，而ID不是，你可以利用这一点来区分它们，并在循环中将类别名称追加到以ID为索引的字典中的列表中：

r = '''B0027DQHA0  Movies & TV, TV  Music, Classical0756400120  Books, Literature & Fiction, Anthologies & Literary Collections, General  Books, Literature & Fiction, United States  Books, Science Fiction & Fantasy, Science Fiction, Anthologies  Books, Science Fiction & Fantasy, Science Fiction, Short StoriesB0000012D5  Music, Blues  Music, Pop  Music, R&B'''d = {}for l in r.splitlines():    if l.startswith(' '):        d.setdefault(i, []).append(l.lstrip())    else:        i = lprint(d)

输出结果如下：

{'B0027DQHA0': ['Movies & TV, TV', 'Music, Classical'], '0756400120': ['Books, Literature & Fiction, Anthologies & Literary Collections, General', 'Books, Literature & Fiction, United States', 'Books, Science Fiction & Fantasy, Science Fiction, Anthologies', 'Books, Science Fiction & Fantasy, Science Fiction, Short Stories'], 'B0000012D5': ['Music, Blues', 'Music, Pop', 'Music, R&B']}