我正在尝试构建一个可以与人互动并帮助他们快速获取更新的聊天机器人。以下是我用来从YouTube/谷歌获取搜索结果的代码。请告诉我问题出在哪里？

maya_google_search.py 代码:

import speech_recognitionimport pyttsx3import pywhatkitfrom wikipedia import wikipediaimport wikipedia as googleScrapimport webbrowserengine = pyttsx3.init("sapi5")voices = engine.getProperty("voices")engine.setProperty("voice", voices[1].id)engine.setProperty("rate", 150)def speak(audio):    engine.say(audio)    engine.runAndWait()def takeCommand():    r = speech_recognition.Recognizer()    with speech_recognition.Microphone() as source:        print("listening.............")        r.pause_threshold = 1        r.energy_threshold = 300        audio = r.listen(source,0,4)    try:        print("Understanding............")        query = r.recognize_google(audio, language='en-in')        print(f"You said: {query}\n")    except Exception as e:        print("Say that again")        speak("Say that again")        return "None"        return queryquery = takeCommand().lower()def Googlesearch(query):        if "google" in query:        query = query.replace("Maya", "")        query = query.replace("google search", "")        query = query.replace("google", "")        speak("This is what I found on Google.....")                try:            pywhatkit.search(query)            result = googleScrap.summary(query,sentences=2)            speak("According to Google..........")            speak(result)                except:            speak("No speakable output available")def Youtubesearch(query):    if "youtube" in query:        query = query.replace("Maya", "")        query = query.replace("youtube search", "")        query = query.replace("youtube", "")        speak("This is what I found for your search!")         web = "https://www.youtube.com/results?search_query=" + query        webbrowser.open(web)        pywhatkit.playonyt(query)                speak("Done, sir")

maya_ai.py 代码:

import pyttsx3import speech_recognitionengine = pyttsx3.init("sapi5")voices = engine.getProperty("voices")engine.setProperty("voice", voices[1].id)engine.setProperty("rate", 150)def speak(audio):    engine.say(audio)    engine.runAndWait()    def takeCommand():    r = speech_recognition.Recognizer()    with speech_recognition.Microphone() as source:        print("listening.............")        r.pause_threshold = 1        r.energy_threshold = 300        audio = r.listen(source,0,4)    try:        print("Understanding............")        query = r.recognize_google(audio, language='en-in')        print(f"You said: {query}\n")        # speak(query)    except Exception as e:        print("Say that again")        return "None"        return queryif __name__ == "__main__":        while True:        query = takeCommand().lower()        if "wake up" in query:            from maya_greeting import greetMe            greetMe()            while True:                query = takeCommand().lower()                if "go to sleep" in query:                    speak("Ok sir, You can call me anytime...")                    break                                elif "hello" in query:                    speak("Hello Sir, how are you?")                elif "i am fine" in query:                    speak("That's really great to know sir....")                elif "how are you":                    speak("i am perfectly alright sir.")                elif "thank you" in query:                    speak("you're welcome sir")                elif "google" in query:                    from maya_google_search import Googlesearch                    Googlesearch(query)                elif "youtube" in query:                    from maya_google_search import Youtubesearch                    Youtubesearch(query)                                elif "wikipedia" in query:                    from maya_google_search import Wikisearch                    Wikisearch(query)

如果我说“谷歌 @人名”，它只会打印我说的话，然后说“我很好，先生”或者什么也不说。

请帮帮我。

回答：

更改

elif "how are you":

为

elif "how are you" in query:

然后你需要添加一个最终的 else 语句，以防之前的条件都没有触发